If the acceleration due to gravity is 10 ms-2 and the units of length and time are changed in kilometer and hour respectively, the numerical value of the acceleration is

Question

If the acceleration due to gravity is 10 ms-2 and the units of length and time are changed in kilometer and hour respectively, the numerical value of the acceleration is (A) 360000 (B) 72,000 (C) 36,000 (D) 129600

Tardigrade Admin · Accepted Answer

n2 = n1[(L1/L2)]1[(T1/T2)]-2 =10[(meter/km)]1[(s/hr)]-2 n2=10[(m/103m)]1[(s/3600s)]-2 =129600

Q. If the acceleration due to gravity is $10 m s^{- 2}$ and the units of length and time are changed in kilometer and hour respectively, the numerical value of the acceleration is

$360000$

$72, 000$

$36, 000$

$129600$

$n_{2} = n_{1} [\frac{L _{1}}{L _{2}}]^{1} [\frac{T _{1}}{T _{2}}]^{- 2}$
$= 10 [\frac{m e t er}{km}]^{1} [\frac{s}{h r}]^{- 2}$
$n_{2} = 10 [\frac{m}{1 0 ^{3} m}]^{1} [\frac{s}{3600 s}]^{- 2}$
$= 129600$

Q. If the acceleration due to gravity is 10ms−2 and the units of length and time are changed in kilometer and hour respectively, the numerical value of the acceleration is

360000

72,000

36,000

129600