Question

If the acceleration-displacement graph of simple harmonic motion of a particle is given, then the time period of the particle will be

• A. $\text{2}\pi$
• B. $\text{3}\pi$
• C. $4\pi$
• D. $\text{5}\pi$

Answer 1

Answer: (A)

Slope of acceleration-displacement graph $=-{\omega }^2$ $\therefore$ ${\omega }^2=\tan {45}^o=1$ $\therefore$ $\omega =1$ But $\omega =\frac{2\pi }{T}=1$ $\therefore$ $T=2\pi$