Question

If the acceleration-displacement graph of simple harmonic motion of a particle is given, then the time period of the particle will be

• A. $ \text{2}\pi $
• B. $ \text{3}\pi $
• C. $ 4\pi $
• D. $ \text{5}\pi $

Answer 1

Answer: (A)

Slope of acceleration-displacement graph $ =-{{\omega }^{2}} $ $ \therefore $ $ {{\omega }^{2}}=\tan {{45}^{o}}=1 $ $ \therefore $ $ \omega =1 $ But $ \omega =\frac{2\pi }{T}=1 $ $ \therefore $ $ T=2\pi $