Question

If temperature is increased by $1K$ at constant volume, then work done on the gas is:

• A. $\frac{5}{2}R$
• B. $\frac{3}{2}R$
• C. zero
• D. $\frac{1}{2}R$

Answer 1

Answer: (C)

Work done on a gas is given by $W=P\Delta V$
where P is pressure, $\Delta V$ the change in volume.
Given $\Delta V=0,$
therefore $W=P\times 0=0$