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Q.
If temperature is increased by $1 \,K$ at constant volume, then work done on the gas is:
Jharkhand CECEJharkhand CECE 2006Thermodynamics
Solution:
Work done on a gas is given by $ W=P\Delta V $
where P is pressure, $ \Delta V $ the change in volume.
Given $ \Delta V=0, $
therefore $ W=P\times 0=0 $