Question

If $\tan \alpha ,\tan \beta ,\tan \gamma$ are the roots of the equation, $x^3-(a+1)x^2+(b-a)x-b=0,(b-a\ne 1)$ Where $\alpha +\beta +\gamma$ lies between 0 and $\pi$ then $\alpha +\beta +\gamma$ is equal to

• A. $\pi /4$
• B. $\pi /2$
• C. $3\pi /4$
• D. None

Answer 1

Answer: (A)

Correct answer is (a) $\pi /4$