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  4. If tan α, tan β, tan γ are the roots of the equation, x3-(a+1) x2+(b-a) x-b=0,(b-a ≠ 1) Where α+β+γ lies between 0 and π then α+β+γ is equal to

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Q. If $\tan \alpha, \tan \beta, \tan \gamma$ are the roots of the equation, $x^3-(a+1) x^2+(b-a) x-b=0,(b-a \neq 1)$ Where $\alpha+\beta+\gamma$ lies between 0 and $\pi$ then $\alpha+\beta+\gamma$ is equal to

Complex Numbers and Quadratic Equations

Solution:

Correct answer is (a) $\pi / 4$