Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If tan A =(1/2) and tan B =(1/3), then value of A + B is
Q. If
tan
A
=
2
1
and
tan
B
=
3
1
, then value of
A
+
B
is
1883
227
Trigonometric Functions
Report Error
A
π
14%
B
6
π
37%
C
2
π
22%
D
4
π
28%
Solution:
tan
(
A
+
B
)
=
1
−
t
a
n
A
t
a
n
B
t
a
n
A
+
t
a
n
B
=
1
−
2
1
⋅
3
1
2
1
+
3
1
=
5/6
5/6
=
1
∴
A
+
B
=
4
5
∘
=
4
π