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Q. If $\tan A =\frac{1}{2}$ and $\tan B =\frac{1}{3}$, then value of $A + B$ is

Trigonometric Functions

Solution:

$\tan ( A + B )=\frac{\tan\, A +\tan \,B }{1-\tan \,A \tan \,B }=\frac{\frac{1}{2}+\frac{1}{3}}{1-\frac{1}{2} \cdot \frac{1}{3}}=\frac{5 / 6}{5 / 6}=1$
$\therefore A + B =45^{\circ}=\frac{\pi}{4}$