Q.
If tan−12 and tan−13 are two angles of a triangle, then the third angle is
2103
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J & K CETJ & K CET 2009Inverse Trigonometric Functions
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Solution:
Given two angles are tan−12 and tan−13. Let third angle be θ,
then, tan−12+tan−13+θ=180o ⇒tan−1(1−2×32+3)=180o−θ ⇒−55=tan(180o−θ)=−tanθ ⇒tanθ=1=tan4π ⇒θ=4π