If Tc is the critical temperature of the gas and Tb is the Boyle's temperature then the correct relation between Tc and Tb is

Question

If Tc is the critical temperature of the gas and Tb is the Boyle's temperature then the correct relation between Tc and Tb is (A) TC = (4/27)Tb (B) TC = (27/6)Tb (C) TC = (8/27)Tb (D) TC = (27/8)Tb

Tardigrade Admin · Accepted Answer

Critical temperature is given by TC = (8a/27 bR) and Boyles temperature is given by Tb = (a/bR) ∴ TC = (8/27) Tb

Q. If $T_{c}$ is the critical temperature of the gas and $T_{b}$ is the Boyle's temperature then the correct relation between $T_{c}$ and $T_{b}$ is

$T_{C} = \frac{4}{27} T_{b}$

$T_{C} = \frac{27}{6} T_{b}$

$T_{C} = \frac{8}{27} T_{b}$

$T_{C} = \frac{27}{8} T_{b}$

Critical temperature is given by $T_{C} = \frac{8 a}{27 b R}$
and Boyles temperature is given by $T_{b} = \frac{a}{b R}$
$∴ T_{C} = \frac{8}{27} T_{b}$

Q. If Tc​ is the critical temperature of the gas and Tb​ is the Boyle's temperature then the correct relation between Tc​ and Tb​ is

TC​=274​Tb​

TC​=627​Tb​

TC​=278​Tb​

TC​=827​Tb​