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Q.
If $T_{c}$ is the critical temperature of the gas and $T_{b}$ is
the Boyle's temperature then the correct relation between
$T_{c}$ and $T_{b}$ is
States of Matter
Solution:
Critical temperature is given by $T_{C} = \frac{8a}{27 bR}$
and Boyles temperature is given by $T_{b} = \frac{a}{bR}$
$\therefore T_{C} = \frac{8}{27} T_{b}$