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Q. If $T_{c}$ is the critical temperature of the gas and $T_{b}$ is the Boyle's temperature then the correct relation between $T_{c}$ and $T_{b}$ is

States of Matter

Solution:

Critical temperature is given by $T_{C} = \frac{8a}{27 bR}$
and Boyles temperature is given by $T_{b} = \frac{a}{bR}$
$\therefore T_{C} = \frac{8}{27} T_{b}$