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Tardigrade
Question
Mathematics
If sin θ = sin 15°+ sin 45°, where 0° < θ < 180°, then θ is equal to
Q. If
s
in
θ
=
s
in
1
5
∘
+
s
in
4
5
∘
, where
0
∘
<
θ
<
18
0
∘
, then
θ
is equal to
5144
185
Trigonometric Functions
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A
4
5
∘
14%
B
15
0
∘
14%
C
6
0
∘
26%
D
7
5
∘
46%
Solution:
We have,
s
in
θ
=
s
in
1
5
∘
+
s
in
4
5
∘
s
in
θ
=
2
s
in
(
2
15
+
45
)
∘
cos
(
2
15
−
45
)
∘
=
2
s
in
3
0
∘
cos
1
5
∘
=
2
×
2
1
cos
1
5
∘
=
cos
1
5
∘
⇒
s
in
θ
=
s
in
(
90
−
15
)
∘
⇒
θ
=
7
5
∘