If sin θ=(a/b), then cos θ and tan θ in terms of a and b are:

Question

If sin θ=(a/b), then cos θ and tan θ in terms of a and b are: (A) (√b2-a2/b) and (b/√b2-a2) (B) (b/√b2-a2) and (a/√b2-a2) (C) (√a2-b2/a) and (b/√a2-b2) (D) (√b2-a2/b) and (a/√b2-a2)

Tardigrade Admin · Accepted Answer

text Apply cos θ=( text Side adjacent to θ/ text Hypotenuse ) tan θ=( text Side opposite to θ/ text Side adjacent to θ)

Q. If $sin θ = \frac{a}{b}$ , then $cos θ$ and $tan θ$ in terms of $a$ and $b$ are:

$\frac{b ^{2} - a ^{2}}{b}$ and $\frac{b}{b ^{2} - a ^{2}}$

$\frac{b}{b ^{2} - a ^{2}}$ and $\frac{a}{b ^{2} - a ^{2}}$

$\frac{a ^{2} - b ^{2}}{a}$ and $\frac{b}{a ^{2} - b ^{2}}$

$\frac{b ^{2} - a ^{2}}{b}$ and $\frac{a}{b ^{2} - a ^{2}}$

$Apply cos θ = \frac{Side adjacent to θ}{Hypotenuse}$
$tan θ = \frac{Side opposite to θ}{Side adjacent to θ}$

Q. If sinθ=ba​, then cosθ and tanθ in terms of a and b are:

bb2−a2​​ and b2−a2​b​

b2−a2​b​ and b2−a2​a​

aa2−b2​​ and a2−b2​b​

bb2−a2​​ and b2−a2​a​