Question

If ${\sin }^{-1}(\sin 5)+{\cos }^{-1}(\cos 10)+{\tan }^{-1}(\tan (-6))+{\cot }^{-1}(\cot (-10))=a\pi +b$ then $(a-b)$ equals

• A. 13
• B. 25
• C. 29
• D. 30

Answer 1

Answer: (C)

$a\pi +b=8\pi -21$.