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Question
Mathematics
If sin-1 a + sin-1b + sin-1c = π , then find the value of a√1-a2+b√1-b2+c√1-c2.
Q. If
s
i
n
−
1
a
+
s
i
n
−
1
b
+
s
i
n
−
1
c
=
π
, then find the value of
a
1
−
a
2
+
b
1
−
b
2
+
c
1
−
c
2
.
2777
234
Inverse Trigonometric Functions
Report Error
A
ab
c
13%
B
a
+
b
+
c
17%
C
a
1
×
b
1
×
c
1
16%
D
2
ab
c
55%
Solution:
Let
s
i
n
−
1
a
=
x
∴
a
=
s
in
x
s
i
n
−
1
b
=
y
∴
b
=
s
in
y
s
i
n
−
1
c
=
z
∴
c
=
s
in
z
∴
a
1
−
a
2
+
b
1
−
b
2
+
c
1
−
c
2
=
s
in
x
cos
x
+
s
in
<
b
r
/
>
ycosy
+
s
in
zcosz
=
(
1/2
)
(
s
in
2
x
+
s
in
2
y
+
s
in
2
z
)
=
(
1/2
)
(
4
s
in
x
s
in
y
s
in
z
)
=
2
s
in
x
s
in
y
s
in
z
=
2
ab
c