If S=sin2p-1/2 sin(2p) (sin2p) +1/3 sin(3p) (sin3p)-(1/4) sin(4p) (sin4p)+ ldots ∞ then tanS=

Question

If S=sin2p-1/2 sin(2p) (sin2p) +1/3 sin(3p) (sin3p)-(1/4) sin(4p) (sin4p)+ ldots ∞ then tanS=  (A)  (cos2 p/1+cos p ⋅ sin p)  (B)  (sin2 p/1+cos p ⋅ sin p)  (C)  (sin2 p/1+cos 2p )  (D)  0

Tardigrade Admin · Accepted Answer

Correct answer is (b) (sin2 p/1+cos p ⋅ sin p)

Q. If $S = s i n^{2} p - 1/2 s in (2 p) (s i n^{2} p)$ $+ 1/3 s in (3 p) (s i n^{3} p) - \frac{1}{4} s in (4 p)$ $(s i n^{4} p) + \dots \infty$ then $t an S =$

$\frac{co s ^{2} p}{1 + cos p \cdot s in p}$

$\frac{s i n ^{2} p}{1 + cos p \cdot s in p}$

$\frac{s i n ^{2} p}{1 + cos 2 p}$

$0$

Correct answer is (b) $\frac{s i n ^{2} p}{1 + cos p \cdot s in p}$

Q. If S=sin2p−1/2sin(2p)(sin2p) +1/3sin(3p)(sin3p)−41​sin(4p) (sin4p)+…∞ then tanS=

1+cosp⋅sinpcos2p​

1+cosp⋅sinpsin2p​

1+cos2psin2p​

0

Correct answer is (b) 1+cosp⋅sinpsin2p​

Q. If $S = s i n^{2} p - 1/2 s in (2 p) (s i n^{2} p)$ $+ 1/3 s in (3 p) (s i n^{3} p) - \frac{1}{4} s in (4 p)$ $(s i n^{4} p) + \dots \infty$ then $t an S =$

$\frac{co s ^{2} p}{1 + cos p \cdot s in p}$

$\frac{s i n ^{2} p}{1 + cos p \cdot s in p}$

$\frac{s i n ^{2} p}{1 + cos 2 p}$

$0$

Correct answer is (b) $\frac{s i n ^{2} p}{1 + cos p \cdot s in p}$