If relation R defined on the set A= 1,2,3,4,5 by R= (x, y):|x2-y2|

Question

If relation R defined on the set A= 1,2,3,4,5 by R= (x, y):|x2-y2|<16 then R is (A)  1, 1, 2, 1, 3, 1, 4, 1, 2, 3 (B) 2, 2, 3, 2, 4, 2, 2, 4 (C)  3, 3, 3, 4, 5, 4, 4, 3, 3, 1 (D) None of these

Tardigrade Admin · Accepted Answer

Here R = x , y :| x 2- y 2|<16 and given A=1,2,3,4,5 ∴ R =1,1,1,2,1,3,1,4,2,1,2,2,2,3,2,4,3,1, 3,2,3,3,3,4,4,1,4,2,4,3,4,44,5,5,4 5,5

Q. If relation $R$ defined on the set $A = {1, 2, 3, 4, 5}$ by $R = {(x, y) : ∣ ∣ x^{2} - y^{2} ∣ ∣ < 16}$ then $R$ is

$1, 1, 2, 1, 3, 1, 4, 1, 2, 3$

$2, 2, 3, 2, 4, 2, 2, 4$

$3, 3, 3, 4, 5, 4, 4, 3, 3, 1$

None of these

Here $R = x, y : ∣ x 2 - y 2∣ < 16$
and given $A = 1, 2, 3, 4, 5$
$∴ R = 1, 1, 1, 2, 1, 3, 1, 4, 2, 1, 2, 2, 2, 3, 2, 4, 3, 1,$
$3, 2, 3, 3, 3, 4, 4, 1, 4, 2, 4, 3, 4, 44, 5, 5, 4$
$5, 5$

Q. If relation R defined on the set A={1,2,3,4,5} by R={(x,y):∣∣​x2−y2∣∣​<16} then R is

1,1,2,1,3,1,4,1,2,3

2,2,3,2,4,2,2,4

3,3,3,4,5,4,4,3,3,1