If ratio of amplitude of two interferring source is 3: 5. Then ratio of intensity of maxima and minima in interference pattern will be:

Question

If ratio of amplitude of two interferring source is 3: 5. Then ratio of intensity of maxima and minima in interference pattern will be: (A) 25: 16 (B) 5: 3 (C) 16: 1 (D) 25: 9

Tardigrade Admin · Accepted Answer

(A1/A2)=(3/5) (I max /I min )=((3+5)2/(3-5)2) =(64/4)=(16/1)

Q. If ratio of amplitude of two interferring source is $3 : 5$ . Then ratio of intensity of maxima and minima in interference pattern will be:

$25 : 16$

$5 : 3$

$16 : 1$

$25 : 9$

$\frac{A _{1}}{A _{2}} = \frac{3}{5}$
$\frac{I _{m a x}}{I _{m i n}} = \frac{( 3 + 5 ) ^{2}}{( 3 - 5 ) ^{2}}$
$= \frac{64}{4} = \frac{16}{1}$

Q. If ratio of amplitude of two interferring source is 3:5. Then ratio of intensity of maxima and minima in interference pattern will be:

25:16

5:3

16:1

25:9