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  4. If ratio of amplitude of two interferring source is 3: 5. Then ratio of intensity of maxima and minima in interference pattern will be:

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Q. If ratio of amplitude of two interferring source is $3: 5$. Then ratio of intensity of maxima and minima in interference pattern will be:

Solution:

$\frac{A_{1}}{A_{2}}=\frac{3}{5}$
$\frac{I_{\max }}{I_{\min }}=\frac{(3+5)^{2}}{(3-5)^{2}}$
$=\frac{64}{4}=\frac{16}{1}$