If rate constant of a reaction is 4.606 × 10-3 s -1 then the time required for the completion of 90 % of the reaction is

Question

If rate constant of a reaction is 4.606 × 10-3 s -1 then the time required for the completion of 90 % of the reaction is (A) 100 s (B) 200 s (C) 400 s (D) 500 s

Tardigrade Admin · Accepted Answer

It is first order reaction since unit of the rate constant is s -1 t=(2.303/k) log (a/a-x) =(2.303/4.606 × 10-3) log (100/10) =0.5 × 103 =500 s

Q. If rate constant of a reaction is $4.606 \times 1 0^{- 3} s^{- 1}$ then the time required for the completion of $90%$ of the reaction is

100 s

200 s

400 s

500 s

It is first order reaction since unit of the rate constant is $s^{- 1}$
$t = \frac{2.303}{k} lo g \frac{a}{a - x}$
$= \frac{2.303}{4.606 \times 1 0 ^{- 3}} lo g \frac{100}{10}$
$= 0.5 \times 1 0^{3}$
$= 500 s$

Q. If rate constant of a reaction is 4.606×10−3s−1 then the time required for the completion of 90% of the reaction is