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Relations and Functions - Part 2
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Solution:
Here, R is not reflexive; as x cannot wife of x,R is not symmetric, as if x is wife of y, then y is husband (not wife) of x and R is transitive as transitivity is not contradicted in this case. Whenever (x,y)∈R, then (y,z)∈/R for any z as if x is wife of y, then y is a male and a male cannot be a wife.