Question

If $R$ is remainder when $6^{83}+8^{83}$ is divided by 49 then $R/5=$

• A. 35
• B. 7
• C. 28
• D. 4

Answer 1

Answer: (B)

Given $=(7-1{)}^{83}+(7+1{)}^{83}=(7+1{)}^{83}-(1-7{)}^{83}$ $=\mathrm{2.7.83}+49I,I$ is integer
$=49I+23\times 49+35\therefore R=35$
$\therefore R/5=7$