If power dissipated in the 9 Ω resistor in the circuit shown is 36 watt, the potential difference across the 2 Ω resistor is

Question

If power dissipated in the 9 Ω resistor in the circuit shown is 36 watt, the potential difference across the 2 Ω resistor is (A) 4 volt (B) 8 volt (C) 10 volt (D) 2 volt

Tardigrade Admin · Accepted Answer

Electric power, p=i2 R ∴ Current, I=√(p/R) Fro resistance of 9 Ω i1=√(36/9)=√4=2 A i2=(i1 × R/6)=(2 × 9/6)=3 A i-i1+i2=2+3=5 A V2=I R2=5 × 2=10 V

Q. If power dissipated in the $9 Ω$ resistor in the circuit shown is $36$ watt, the potential difference across the $2 Ω$ resistor is

4 volt

8 volt

10 volt

2 volt

Electric power, $p = i^{2} R$
$∴$ Current, $I = \frac{p}{R}$
Fro resistance of $9Ω$
$i_{1} = \frac{36}{9} = 4 = 2 A$
$i_{2} = \frac{i _{1} \times R}{6} = \frac{2 \times 9}{6} = 3 A$
$i - i_{1} + i_{2} = 2 + 3 = 5 A$
$V_{2} = I R_{2} = 5 \times 2 = 10 V$

Q. If power dissipated in the 9Ω resistor in the circuit shown is 36 watt, the potential difference across the 2Ω resistor is