Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If P(n):2n < n! Then the smallest positive integer for which P(n) is true if
Q. If
P
(
n
)
:
2
n
<
n
!
Then the smallest positive integer for which P(n) is true if
1870
177
KCET
KCET 2020
Permutations and Combinations
Report Error
A
2
38%
B
3
10%
C
4
40%
D
5
12%
Solution:
For
n
=
1
,
2
,
3
,
2
n
>
n
!
P
(
4
)
:
2
4
<
4
!
So, smallest positive integer,
n
=
4
.