We have statements p,q→T and r,s→F
Option (a)(q∧r)∨(∼p∧s)≡(T∧F)∨(F∧F) ≡F∨F≡F
Option (b) (∼p→q)↔(r∧s)≡(p∨q)→(r∨s) (∵p→q≡∼p∨q) ≡(∼p∨q)∨(r∧s)∧((p∨q)∨(∼r∧s))) (∵p↔q≡(∼p∨q)∧(p∨−q)) ≡(∼(T∨T)∨(F∧F)∧((T∨F)∨(∼(F∧F))) ≡(F∨F)∧(T∨T)≡F∧T≡F
Option (c) (p→q)∨(r↔s) ≡(∼p∨q)∨((∼r∨s)∧(r∨∼s))(∵p→q≡∼p∨q) ≡(F∨T)∨((T∨F)∧(F∨T)) ≡T∨(T∧T)≡T.∨T≡T
Option (d) do similar as option (a).