If only one hundredth part of total current flowing in the circuit is to be passed through a galvanometer of resistance G , then the value of shunt resistance required will be -

Question

If only one hundredth part of total current flowing in the circuit is to be passed through a galvanometer of resistance G , then the value of shunt resistance required will be - (A) (G/10) (B) (G/100) (C) (G/99) (D) (G/999)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-rupvhzqt5j6s1auu.jpg" /> Using Kirchoff's Loop law igG=(i - ig)S (i/100)G=(i - (i/100))S (G/100)=(99 S/100) S=(G/99)

Q. If only one hundredth part of total current flowing in the circuit is to be passed through a galvanometer of resistance $G$ , then the value of shunt resistance required will be -

$\frac{G}{10}$

$\frac{G}{100}$

$\frac{G}{99}$

$\frac{G}{999}$

Using Kirchoff's Loop law
$i_{g} G = (i - i_{g}) S$
$\frac{i}{100} G = (i - \frac{i}{100}) S$
$\frac{G}{100} = \frac{99 S}{100}$
$S = \frac{G}{99}$

Q. If only one hundredth part of total current flowing in the circuit is to be passed through a galvanometer of resistance G , then the value of shunt resistance required will be -

10G​

100G​

99G​

999G​