Question

If only one hundredth part of total current flowing in the circuit is to be passed through a galvanometer of resistance $G$ , then the value of shunt resistance required will be -

• A. $\frac{G}{10}$
• B. $\frac{G}{100}$
• C. $\frac{G}{99}$
• D. $\frac{G}{999}$

Answer 1

Answer: (C)

Using Kirchoff's Loop law
$i_{g}G=\left(i - i_{g}\right)S$
$\frac{i}{100}G=\left(i - \frac{i}{100}\right)S$
$\frac{G}{100}=\frac{99 S}{100}$
$S=\frac{G}{99}$