If one mole of ammonia and one mole of hydrogen chloride are mixed in a closed container to form ammonium chloride gas, then

Question

If one mole of ammonia and one mole of hydrogen chloride are mixed in a closed container to form ammonium chloride gas, then (A) Δ H > Δ u (B) Δ H = Δ u (C) Δ H < Δ u (D) there is no relationship

Tardigrade Admin · Accepted Answer

underset1 molNH 3(g)+ underset1 molHCl (g) longrightarrow underset1 molNH 4 Cl (g) Δ H=Δ U+ng R T ng= Number of moles of product - number of moles of reactant =1-2=-1 Δ H=Δ U-R T ∴ Δ H< Δ U

Q. If one mole of ammonia and one mole of hydrogen chloride are mixed in a closed container to form ammonium chloride gas, then

$Δ H > Δ u$

$Δ H = Δ u$

$Δ H < Δ u$

there is no relationship

$1 m o l N H_{3} (g) + 1 m o l H Cl (g) ⟶ 1 m o l N H_{4} Cl (g)$

$Δ H = Δ U + n_{g} RT$

$n_{g} =$ Number of moles of product

- number of moles of reactant

$= 1 - 2 = - 1$

$Δ H = Δ U - RT$

$∴ Δ H < Δ U$

Q. If one mole of ammonia and one mole of hydrogen chloride are mixed in a closed container to form ammonium chloride gas, then

ΔH>Δu

ΔH=Δu

ΔH<Δu

there is no relationship

1molNH3​(g)​+1molHCl(g)​⟶1molNH4​Cl(g)​ ΔH=ΔU+ng​RT ng​= Number of moles of product - number of moles of reactant =1−2=−1 ΔH=ΔU−RT ∴ΔH<ΔU

$Δ H > Δ u$

$Δ H = Δ u$

$Δ H < Δ u$

$1 m o l N H_{3} (g) + 1 m o l H Cl (g) ⟶ 1 m o l N H_{4} Cl (g)$

$Δ H = Δ U + n_{g} RT$

$n_{g} =$ Number of moles of product

- number of moles of reactant

$= 1 - 2 = - 1$

$Δ H = Δ U - RT$

$∴ Δ H < Δ U$