Given that O(A)=2×3,O(B)=3×2 and O(C)=3×3 ⇒O(A′)=3×2,O(B′)=2×3
(a) CB+A′
Now order of CB = (order of C) (order of B)
= (order of C is 3×3) (order of B is 3×2)
= order of CB is 3×2
Since O(A′)=3×2 ∴ Matrix CB + A' can be determined.
(b) O(BA)=3×3
and O(C)=3×3 ∴ Matrix BAC can be determined.
(c) C(A+B′)′ O(A+B′)=2×3 ⇒O(A+B′)′=3×2
and O(C)=3×3 ∴ Matrix C(A+B′)′ can be determined.
(d) C(A+B′) O(A+B′)=2×3
and O(C)=3×3 ∴ Matrix C(A+B′) cannot be determined