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Question
Chemistry
If ν1 is the frequency of series limit of Lyman series, ν2 is the frequency of first line of Lyman series and ν3 be the frequency of the series limit of Balmer series. Then
Q. If
ν
1
is the frequency of series limit of Lyman series,
ν
2
is the frequency of first line of Lyman series and
ν
3
be the frequency of the series limit of Balmer series. Then
362
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A
ν
1
+
ν
2
=
ν
3
20%
B
ν
2
−
ν
1
=
ν
3
0%
C
ν
1
−
ν
2
=
ν
3
60%
D
v
3
=
2
1
(
v
1
+
v
2
)
20%
Solution:
v
1
=
c
R
(
1
2
1
−
∞
2
1
)
=
c
R
v
2
=
c
R
(
1
2
1
−
2
2
1
)
=
4
3
c
R
v
3
=
c
R
(
2
2
1
−
∞
)
=
4
c
R
So
v
1
−
v
2
=
v
3