Question

If net reactance in a circuit is $\sqrt{3}$ times of resistance, then find phase difference.

• A. Zero
• B. $30^{\circ }$
• C. $60^{\circ }$
• D. Data is incomplete

Answer 1

Answer: (C)

$\tan \theta =\frac{X_L-X_C}{R}$
where, $X_L-X_C$ is the net reactance of the circuit.
$\Rightarrow \theta ={\tan }^{-1}\frac{X_L-X_C}{R}$
$\Rightarrow X_C=0$
$\Rightarrow \theta ={\tan }^{-1}\left(\frac{\sqrt{3}R}{R}\right)$
$\Rightarrow \theta ={\tan }^{-1}(\sqrt{3})=60^{\circ }$
$=\frac{\pi }{3}$