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  4. If net reactance in a circuit is √3 times of resistance, then find phase difference.

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Q. If net reactance in a circuit is $\sqrt{3}$ times of resistance, then find phase difference.

Alternating Current

Solution:

$\tan \theta=\frac{X_{L}-X_{C}}{R}$
where, $X_{L}-X_{C}$ is the net reactance of the circuit.
$\Rightarrow \quad \theta=\tan ^{-1} \frac{X_{L}-X_{C}}{R}$
$ \Rightarrow X_{C}=0$
$\Rightarrow \quad \theta=\tan ^{-1}\left(\frac{\sqrt{3} R}{R}\right)$
$\Rightarrow \theta=\tan ^{-1}(\sqrt{3})=60^{\circ}$
$=\frac{\pi}{3}$