Given, nCr+3nCr+1+3nCr+2+nCr+3=15C9,
As upper suffixes are same, lower suffixes are in increasing order and coefficients of the terms are the coefficients of the expansion of (1+x)3. ∴nCr+3nCr+1+3nCr+2+nCr+3 =n+3Cr+3=15C9=n+3Cn−r
(Using nCr+nCr+1=n+1Cr+1 and nCr=nCn−r) ⇒n+3=15 and r+3=9,r+3+9=15
[By using nCx=nCy⇒x+y=n or x=y] ⇒n=12,r=6 or 3.