If n represents the actual number of deflections in a converted galvanometer of resistance G and shunt resistance S. Then the total current I when its figure of merit is K will be :

Question

If n represents the actual number of deflections in a converted galvanometer of resistance G and shunt resistance S. Then the total current I when its figure of merit is K will be : (A) ( KS /( S + G )) (B) (( G + S )/ nKS ) (C) ( nKS /( G + S )) (D) ( nK ( G + S )/ S )

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/8f3f93803e0ed286cff7bdae1ab409cf-.png" /> Figure of merit (Ig/θ)=K I g = Kn I =( I g / s )( G + S ) I =( nK / S )( G + S )

Q. If $n$ represents the actual number of deflections in a converted galvanometer of resistance $G$ and shunt resistance $S$ . Then the total current I when its figure of merit is $K$ will be :

$\frac{K S}{( S + G )}$

$\frac{( G + S )}{n K S}$

$\frac{n K S}{( G + S )}$

$\frac{n K ( G + S )}{S}$

Figure of merit $\frac{I _{g}}{θ} = K$
$I_{g} = K n$
$I = \frac{I _{g}}{s} (G + S)$
$I = \frac{n K}{S} (G + S)$

Q. If n represents the actual number of deflections in a converted galvanometer of resistance G and shunt resistance S. Then the total current I when its figure of merit is K will be :

(S+G)KS​

nKS(G+S)​

(G+S)nKS​

SnK(G+S)​