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Q. If $n$ represents the actual number of deflections in a converted galvanometer of resistance $G$ and shunt resistance $S$. Then the total current I when its figure of merit is $K$ will be :

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Solution:

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Figure of merit $\frac{I_{g}}{\theta}=K$
$ I _{ g }= Kn $
$I =\frac{ I _{ g }}{ s }( G + S ) $
$I =\frac{ nK }{ S }( G + S )$