Question

If $n(A)=5$ and $n(B)=7$, then the number of relations on $A\times B$ is

• A. $2^{35}$
• B. $2^{49}$
• C. $2^{25}$
• D. $2^{70}$
• E. $2^{35\times 35}$

Answer 1

Answer: (A)

Given, $n(A)=5$ and $n(B)=7$
Therefore, number of relations on
$A\times B=2^{[\ln (A)\times n(B)]}$ $=2^{(5\times 7)}=2^{(35)}$