If molar mass of AB is 95 g mol -1 and a is edge length, then the density of crystal structure is

Question

If molar mass of AB is 95 g mol -1 and a is edge length, then the density of crystal structure is (A) (4 × 95/ a 3 × N A ) (B) (4 N A / a 3 × 95) (C) (2 × 95/ a 3 × N ) (D) (2 N A / a 3 × 95)

Tardigrade Admin · Accepted Answer

Here number of AB per unit cell =4 Density =(Z × M/a3 N0) =(4 × 95/a3 N0)

Q. If molar mass of $A B$ is $95 g m o l^{- 1}$ and a is edge length, then the density of crystal structure is

$\frac{4 \times 95}{a ^{3} \times N _{A}}$

$\frac{4 N _{A}}{a ^{3} \times 95}$

$\frac{2 \times 95}{a ^{3} \times N}$

$\frac{2 N _{A}}{a ^{3} \times 95}$

Here number of $A B$ per unit cell $= 4$
Density $= \frac{Z \times M}{a ^{3} N _{0}}$
$= \frac{4 \times 95}{a ^{3} N _{0}}$

Q. If molar mass of AB is 95gmol−1 and a is edge length, then the density of crystal structure is

a3×NA​4×95​

a3×954NA​​

a3×N2×95​

a3×952NA​​