If mA gram of a metal A displaces mB gram of another metal B from its salt solution and if the equivalent mass are EA and EB respectively then equivalent mass of A can be expressed as:

Question

If mA gram of a metal A displaces mB gram of another metal B from its salt solution and if the equivalent mass are EA and EB respectively then equivalent mass of A can be expressed as: (A) EA=(mA/mB) × EB (B) EA=(mA× mB/EB) (C) EA=(mB/mA)× EB (D) EA=√(mA /mB)× EB

Tardigrade Admin · Accepted Answer

Correct answer is (a) EA=(mA/mB) × EB

Q. If $m_{A}$ gram of a metal $A$ displaces $m_{B}$ gram of another metal B from its salt solution and if the equivalent mass are $E_{A}$ and $E_{B}$ respectively then equivalent mass of $A$ can be expressed as:

$E_{A} = \frac{m _{A}}{m _{B}} \times E_{B}$

$E_{A} = \frac{m _{A} \times m _{B}}{E _{B}}$

$E_{A} = \frac{m _{B}}{m _{A}} \times E_{B}$

$E_{A} = \frac{m _{A}}{m _{B}} \times E_{B}$

Correct answer is (a) $E_{A} = \frac{m _{A}}{m _{B}} \times E_{B}$

Q. If mA​ gram of a metal A displaces mB​ gram of another metal B from its salt solution and if the equivalent mass are EA​ and EB​ respectively then equivalent mass of A can be expressed as:

EA​=mB​mA​​×EB​

EA​=EB​mA​×mB​​

EA​=mA​mB​​×EB​

EA​=mB​mA​​×EB​​

Correct answer is (a) EA​=mB​mA​​×EB​

Q. If $m_{A}$ gram of a metal $A$ displaces $m_{B}$ gram of another metal B from its salt solution and if the equivalent mass are $E_{A}$ and $E_{B}$ respectively then equivalent mass of $A$ can be expressed as:

$E_{A} = \frac{m _{A}}{m _{B}} \times E_{B}$

$E_{A} = \frac{m _{A} \times m _{B}}{E _{B}}$

$E_{A} = \frac{m _{B}}{m _{A}} \times E_{B}$

$E_{A} = \frac{m _{A}}{m _{B}} \times E_{B}$

Correct answer is (a) $E_{A} = \frac{m _{A}}{m _{B}} \times E_{B}$