If Mz = magnetization of a paramagnetic sample, B = external magnetic field, T = absolute temperature, C = curie constant then according to Curie’s law in magnetism, the correct relation is

Question

If Mz = magnetization of a paramagnetic sample, B = external magnetic field, T = absolute temperature, C = curie constant then according to Curie’s law in magnetism, the correct relation is (A) Mz = (T/CB) (B) Mz = (CB/T) (C) C = (Mz/T) (D) C = (T2/Mz)

Tardigrade Admin · Accepted Answer

Here, M2= magnetization of a paramagnetic sample B= external magnetic field T = absolute temperature C= Curie constant Curie's law in magnetism states that in paramagnetic material, the material's magnetization is directly proportional to the applied field, but when temperature increases the relation is reversed, i.e. the magnetization becomes inversely proportional to the temperature. Mathematically, it is written as M2=(C × B/T) ⇒ C=(M2 ⋅ T/B)

Q. If $M_{z}$ = magnetization of a paramagnetic sample, $B$ = external magnetic field, $T$ = absolute temperature, $C$ = curie constant then according to Curie’s law in magnetism, the correct relation is

$M_{z} = \frac{T}{CB}$

$M_{z} = \frac{CB}{T}$

$C = \frac{M _{z}}{T}$

$C = \frac{T ^{2}}{M _{z}}$

Q. If Mz​ = magnetization of a paramagnetic sample, B = external magnetic field, T = absolute temperature, C = curie constant then according to Curie’s law in magnetism, the correct relation is

Mz​=CBT​

Mz​=TCB​

C=TMz​​

C=Mz​T2​

Q. If $M_{z}$ = magnetization of a paramagnetic sample, $B$ = external magnetic field, $T$ = absolute temperature, $C$ = curie constant then according to Curie’s law in magnetism, the correct relation is

$M_{z} = \frac{T}{CB}$

$M_{z} = \frac{CB}{T}$

$C = \frac{M _{z}}{T}$

$C = \frac{T ^{2}}{M _{z}}$