If M, L, T and I stand for mass, length, time and electric current respectively, the dimensional formula for capacitance is:

Question

If M, L, T and I stand for mass, length, time and electric current respectively, the dimensional formula for capacitance is: (A)  [ M-1L2T-4I2 ]  (B)  [ M-1L-2T4I2 ]  (C)  [ ML2T4I2 ]  (D)  [ ML2T-4I-2 ]

Tardigrade Admin · Accepted Answer

Capacitance C=(Ch arg e/Potential)=(q/V)=(Q/W/q)=(q2/W) Dimensions of textC = ( text(Dimensions textof textcharge) text2/ textDimensions textof textwork) =([IT]2/[ML2T-2]) =([I2T2]/[ML2T-2]) =[M-1L-2T4I2]

Q. If M, L, T and I stand for mass, length, time and electric current respectively, the dimensional formula for capacitance is:

$[M^{- 1} L^{2} T^{- 4} I^{2}]$

$[M^{- 1} L^{- 2} T^{4} I^{2}]$

$[M L^{2} T^{4} I^{2}]$

$[M L^{2} T^{- 4} I^{- 2}]$

Q. If M, L, T and I stand for mass, length, time and electric current respectively, the dimensional formula for capacitance is:

[M−1L2T−4I2]

[M−1L−2T4I2]

[ML2T4I2]

[ML2T−4I−2]

Capacitance C=PotentialCharge​=Vq​=W/qQ​=Wq2​ Dimensions of C = Dimensionsofwork(Dimensionsofcharge)2​ =[ML2T−2][IT]2​ =[ML2T−2][I2T2]​ =[M−1L−2T4I2]

$[M^{- 1} L^{2} T^{- 4} I^{2}]$

$[M^{- 1} L^{- 2} T^{4} I^{2}]$

$[M L^{2} T^{4} I^{2}]$

$[M L^{2} T^{- 4} I^{- 2}]$