If m and n are degree and order of (1+y12)2/3=y2, then the value of (m+n/m-n) is

Question

If m and n are degree and order of (1+y12)2/3=y2, then the value of (m+n/m-n) is (A) 3 (B) 4 (C) 5 (D) 2

Tardigrade Admin · Accepted Answer

Given differential equation is (1+((d y/d x))2)2 / 3=((d2 y/d x2)) ⇒ (1+((d y/d x))2)2=((d2 y/d x2))3 Now, Order =n=2 Degree =m=3 Then, (m+n/m-n)=(3+2/3-2)=5

Q. If $m$ and $n$ are degree and order of $(1 + y_{1}^{2})^{2/3} = y_{2}$ , then the value of $\frac{m + n}{m - n}$ is

3

4

5

2

Given differential equation is
$(1 + (\frac{d y}{d x})^{2})^{2/3} = (\frac{d ^{2} y}{d x ^{2}})$
$\Rightarrow (1 + (\frac{d y}{d x})^{2})^{2} = (\frac{d ^{2} y}{d x ^{2}})^{3}$
Now, Order $= n = 2$
Degree $= m = 3$
Then, $\frac{m + n}{m - n} = \frac{3 + 2}{3 - 2} = 5$

Q. If m and n are degree and order of (1+y12​)2/3=y2​, then the value of m−nm+n​ is

3

4

5

2

Given differential equation is (1+(dxdy​)2)2/3=(dx2d2y​) ⇒(1+(dxdy​)2)2=(dx2d2y​)3 Now, Order =n=2 Degree =m=3 Then, m−nm+n​=3−23+2​=5

Q. If $m$ and $n$ are degree and order of $(1 + y_{1}^{2})^{2/3} = y_{2}$ , then the value of $\frac{m + n}{m - n}$ is

Given differential equation is
$(1 + (\frac{d y}{d x})^{2})^{2/3} = (\frac{d ^{2} y}{d x ^{2}})$
$\Rightarrow (1 + (\frac{d y}{d x})^{2})^{2} = (\frac{d ^{2} y}{d x ^{2}})^{3}$
Now, Order $= n = 2$
Degree $= m = 3$
Then, $\frac{m + n}{m - n} = \frac{3 + 2}{3 - 2} = 5$