If M(A ; Z), Mp and Mn denote the masses of the nucleus ZA X, proton and neutron respectively in units of u (1 u =931.5 MeV / c 2) and B E represents its bonding energy in MeV, then

Question

If M(A ; Z), Mp and Mn denote the masses of the nucleus ZA X, proton and neutron respectively in units of u (1 u =931.5 MeV / c 2) and B E represents its bonding energy in MeV, then (A) M(A, Z)=Zp+(A-Z) Mn-B E (B) M(A, Z)=Z M-p+(A-Z) Mn+B E / c2 (C) M(A, Z)=Z Mp+(A-Z) Mn-B E / c2 (D) M(A, Z)=Z Mp+(A-Z) Mn+B E

Tardigrade Admin · Accepted Answer

Z Mp+(A-Z) Mn-M(A, Z) = mass effect =(B ⋅ E/c2) ⇒ M(A, Z)=Z Mp+(A-Z) Mn-(B ⋅ E/c2)

Q. If $M (A; Z), M_{p}$ and $M_{n}$ denote the masses of the nucleus $_{Z}^{A} X$ , proton and neutron respectively in units of $u (1 u = 931.5 M e V / c^{2})$ and $BE$ represents its bonding energy in $M e V$ , then

$M (A, Z) = Z_{p} + (A - Z) M_{n} - BE$

$M (A, Z) = ZM - p + (A - Z) M_{n} + BE / c^{2}$

$M (A, Z) = Z M_{p} + (A - Z) M_{n} - BE / c^{2}$

$M (A, Z) = Z M_{p} + (A - Z) M_{n} + BE$

$Z M_{p} + (A - Z) M_{n} - M (A, Z)$
$=$ mass effect $= \frac{B \cdot E}{c ^{2}}$
$\Rightarrow M (A, Z) = Z M_{p} + (A - Z) M_{n} - \frac{B \cdot E}{c ^{2}}$

Q. If M(A;Z),Mp​ and Mn​ denote the masses of the nucleus ZA​X, proton and neutron respectively in units of u(1u=931.5MeV/c2) and BE represents its bonding energy in MeV, then

M(A,Z)=Zp​+(A−Z)Mn​−BE

M(A,Z)=ZM−p+(A−Z)Mn​+BE/c2

M(A,Z)=ZMp​+(A−Z)Mn​−BE/c2

M(A,Z)=ZMp​+(A−Z)Mn​+BE