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Question
Mathematics
If ( log a/5)=( log b/6)=( log c/7), then b2=
Q. If
5
l
o
g
a
=
6
l
o
g
b
=
7
l
o
g
c
, then
b
2
=
179
154
Logarithms
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A
a
c
B
a
2
C
ab
D
b
c
Solution:
Let
5
l
o
g
a
=
6
l
o
g
b
=
7
l
o
g
c
=
k
⇒
lo
g
a
=
5
k
⇒
a
=
1
0
5
k
lo
g
b
=
6
k
⇒
b
=
1
0
6
k
lo
g
c
=
7
k
⇒
c
=
1
0
7
k
b
2
=
(
1
0
6
k
)
2
=
1
0
12
k
=
1
0
7
k
×
1
0
5
k
=
a
c