Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If log 10 11=p, then log 10((1/110))=
Q. If
lo
g
10
11
=
p
, then
lo
g
10
(
110
1
)
=
38
154
Logarithm
Report Error
A
(
1
+
p
)
−
1
B
−
(
1
+
p
)
C
1
−
p
D
10
p
1
Solution:
lo
g
a
1
=
lo
g
a
−
1
;
lo
g
mn
=
lo
g
m
+
lo
g
n
and
lo
g
a
a
=
1