If log 1 / 3 (3 x-1/x+2) is less than unity then x must lie in the interval -

Question

If log 1 / 3 (3 x-1/x+2) is less than unity then x must lie in the interval - (A) (-∞,-2) ∪(5 / 8, ∞) (B) (-2,5 / 8) (C) (-∞,-2) ∪(1 / 3,5 / 8) (D) (-2,1 / 3)

Tardigrade Admin · Accepted Answer

Correct answer is (a) (-∞,-2) ∪(5 / 8, ∞)

Q. If $lo g_{1/3} \frac{3 x - 1}{x + 2}$ is less than unity then $x$ must lie in the interval -

$(- \infty, - 2) \cup (5/8, \infty)$

$(- 2, 5/8)$

$(- \infty, - 2) \cup (1/3, 5/8)$

$(- 2, 1/3)$

Correct answer is (a) $(- \infty, - 2) \cup (5/8, \infty)$

Q. If log1/3​x+23x−1​ is less than unity then x must lie in the interval -

(−∞,−2)∪(5/8,∞)

(−2,5/8)

(−∞,−2)∪(1/3,5/8)

(−2,1/3)

Correct answer is (a) (−∞,−2)∪(5/8,∞)

Q. If $lo g_{1/3} \frac{3 x - 1}{x + 2}$ is less than unity then $x$ must lie in the interval -

$(- \infty, - 2) \cup (5/8, \infty)$

$(- 2, 5/8)$

$(- \infty, - 2) \cup (1/3, 5/8)$

$(- 2, 1/3)$

Correct answer is (a) $(- \infty, - 2) \cup (5/8, \infty)$