Question

If length of wire is $2m$ and the mass is $80kg$, the tension in wire will be if frequency is $\frac{1}{4}Hz$ :

• A. 400 N
• B. 80 N
• C. 4 N
• D. 4000 N

Answer 1

Answer: (B)

$n=\frac{1}{2l}\sqrt{\left(\frac{T}{m}\right)}$
$\therefore T=(2nl{)}^2\times m$
$={\left(2\times \frac{1}{4}\times 2\right)}^2\times 80$
$=80N$