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Q. If length of wire is $2\, m$ and the mass is $80\, kg$, the tension in wire will be if frequency is $\frac{1}{4} \,Hz$ :

Rajasthan PMTRajasthan PMT 2004Waves

Solution:

$ n=\frac{1}{2 l} \sqrt{\left(\frac{T}{m}\right)}$
$ \therefore T =(2 n l)^{2} \times m $
$=\left(2 \times \frac{1}{4} \times 2\right)^{2} \times 80$
$=80 \,N $