If law of conservation of mass was to hold true, then 20.8 g of BaCl2 on reaction with 9 8 g of H2SO4 will produce 7.3 g of HCl and BaSO4 equal to

Question

If law of conservation of mass was to hold true, then 20.8 g of BaCl2 on reaction with 9 8 g of H2SO4 will produce 7.3 g of HCl and BaSO4 equal to (A) 11.65 g (B) 23.3 g (C) 25.5 g (D) 30.6 g

Tardigrade Admin · Accepted Answer

underset208 g BaCl 2+ underset98 g H 2 SO 4 arrow underset233 g BaSO 2+ underset73 g 2 Hcl Mass of BaSO 4 produced =20.8+9.8-7.3 =23.3 g

Q. If law of conservation of mass was to hold true, then $20.8 g$ of $B a C l_{2}$ on reaction with $98 g$ of $H_{2} S O_{4}$ will produce 7.3 {\,}g of $H Cl$ and $B a S O_{4}$ equal to

11.65 g

23.3 g

25.5 g

30.6 g

$208 g B a C l_{2} + 98 g H_{2} S O_{4} \to 233 g B a S O_{2} + 73 g 2 Hc l$
Mass of $B a S O_{4}$ produced
$= 20.8 + 9.8 - 7.3$
$= 23.3 g$

Q. If law of conservation of mass was to hold true, then 20.8g of BaCl2​ on reaction with 98g of H2​SO4​ will produce 7.3 {\,}g of HCl and BaSO4​ equal to