Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If λ= log 0.001 10000, then anti log 103(λ) is equal to
Q. If
λ
=
lo
g
0.001
10000
, then anti
lo
g
1
0
3
(
λ
)
is equal to
18
96
Continuity and Differentiability
Report Error
A
0.01
B
0.001
C
0.0001
D
0.1
Solution:
λ
=
lo
g
1
0
−
3
(
1
0
4
)
=
3
−
4
∴
anti
lo
g
1
0
3
(
3
−
4
)
=
(
1
0
3
)
3
−
4
=
1
0
−
4
=
0.0001